find the value

IIT JEE 2015 Help › Algebra questions › find the value

g(x)=1/2(x^102)-23(x^101)-45/2(x^2)+1035x.....then find g(46) and g(45/2)????????????

#Mathematics #Algebra

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6 Answers

39

Dr.House ·2009-07-16 21:43:20

wat do u expect us to do?

i say something.

show your working and tell us where u stopped, s that we can help u in a better way

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62

Lokesh Verma ·2009-07-16 22:01:19

g(x)=1/2(x^102)-23(x^101)-45/2(x^2)+1035x.....then find g(46) and g(45/2)????????????

g(x) = x^101{x/2-23} - 45x/2{x-23}

Does this help?

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11

Tarun Kumar Yadav ·2009-07-16 22:27:24

2g(x) = x¹⁰² -46x¹⁰¹ -45x² +1035x

2g(46)= 46¹⁰²- 46¹⁰² -45*4*23²+45*23*2*23

g(46)= -1035

is the answer correct

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3

rocky ·2009-07-16 23:14:09

not getting 0

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3

rocky ·2009-07-19 06:50:27

plz help

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62

Lokesh Verma ·2009-07-21 08:43:44

sumeet i think what tarun has done is absolutely correct...

Why do you want to get zero if it is not :)

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Your Answer

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