cos\theta + isin\theta = e^{i\theta }
put θ = π/2
u will get
i = e^{i\frac{\pi }{2} }
now logi = {i\frac{\pi }{2} }
ilogi = {-\frac{\pi }{2} }
find the value of sin\left(\textrm{log} \left ( \textup{i}^\textup{i} \right ) \right)
cos\theta + isin\theta = e^{i\theta }
put θ = π/2
u will get
i = e^{i\frac{\pi }{2} }
now logi = {i\frac{\pi }{2} }
ilogi = {-\frac{\pi }{2} }