function

f(x)=x^n +4;
then value of f(1)+f'(1)/1! +f"(1)/2! +..... nth derivatiive

10 Answers

62
Lokesh Verma ·

this is directly from taylor's expansion....

f(x-1) then substitute x=2

so i think answer should be 2n+4

1
kishan nageswaran ·

thankz

9
Celestine preetham ·

its of form nCr

9
Celestine preetham ·

so ans is directly

4 + ΣnCr = 4 + 2 ^n

9
Celestine preetham ·

wat is taylors exp ?

62
Lokesh Verma ·

http://wiki.targetiit.com/Taylor%27s_Series

i din read ur last post...

well ur method is simpler i guess...

first thing that struck me was that htis was a taylor expansion's direct question :)

62
Lokesh Verma ·

1
kishan nageswaran ·

i think f(a+h)=f(a)+f'(a)*(a+h)/1!......

9
Celestine preetham ·

wen u diffrentiate term r = n!/r!(n-r)! chk that

62
Lokesh Verma ·

yes celestine.. i am not doubting your solution.. :)

Your Answer

Close [X]