any condition for y ?
or else putting y=1 in the eqn ,
we get f(x)=0
If f(x) = f(xy)+f(\frac{x}{y}) \text{for all } x \epsilon \mathbb{R^{+}} and f(1) = 0 , f ' (1) = 0 , then find the f(x).
Please HelpI just can't make this : f ' (1) = 0 ?
-
UP 0 DOWN 0 0 5
5 Answers
Aditya Bhutra
·2011-12-03 22:59:13
Vivek @ Born this Way
·2011-12-04 00:49:41
No not given i presume. But certainly f(x) = 0 won't satisfy the given criteria, so it isn't a solution. Try finding other.
Vivek @ Born this Way
·2011-12-04 21:55:21
Hmm.. Ok. That's the trivial one and probably the solution for the problem as well. Cause I see no other function goes to the second criteria i.e., f'(1)=0