29Bhaiya i din get ur post ..i also feel that log shud not be there in g(x) ...but how putting x = tank we get g(x) = log(tanx)
in tan3x formula we have - signs ..but here we have + ..
if f(x)= log(1+x1-x) ; g(x) = log(3x+x31+3x2) then find f(g(x)) in terms of f(x).
1) -f(x)
2) 3f(x)
3) [f(x)]3
4) -3f(x)
-
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11 Answers
62This is a good question
but are you sure that g(x) has log around it?
x=tan k
then g(X) = log (tan x)
Then try it..
29
1yup govind's rite bhaiya how by putting x = tank we get g(x) = log(tanx) ...... i did get it either ???[7]
1putin x=i tan y
g(x)=i tan 3y
f(g(x))= 6iy
f(x)=2iy
f(g(x))= 3f(x)
i think she has done / or the book has done the printing error
1the question is the same.....no error in it,...!! g(x) and f(x) has log around it....
62hmm.. sounds interesting vinutha...
Could you tell me the source of the question?
1@nishant sir there ias a image in ur chatbox........plz see it n reply[2][2]..........plz don ignore!!!!!!!