are yaar .... aisa thode hi hai...
ans sab method se ana chahiye... ye maths hai chem nahi..[3]
i think theres no such continuous and differentiable function...
:P
Let f (x + y) = f (x) f (y) for all x and y. Suppose that f (3) = 3 and f '(0) = 11. Then f ' (3) is given by :
opts are : 22,33,44, none of these....
Ans:
I'm getting 33 but the ans reads none of thes
are yaar .... aisa thode hi hai...
ans sab method se ana chahiye... ye maths hai chem nahi..[3]
i think theres no such continuous and differentiable function...
:P
lol... mera dimag aaj ghumne gaya hai....
phir se banate hai suru se...
ani already pointed it.... :(
but abhishek then ur functn cant b λe^(kx).....
i guess this type of sums shall b done widout assumin a functn....
ie the nishant sir has solved, makin use of the diff properties n given values of f(a)
ax does not satisfy for f'(0) as bhaiyya pointed out
so what is the function then [7]no need for this
yes it does not satisfy.........[7].......i think may be this part of question is wrong..[12].....
vaise bhi.......magic math has already written.."BUT ther r a NO. OF mistakes in it...."[1]
no need to find the function so proceed like nishant bhaiyya has done and get the answer (:( which he says is wrong)
uffffffff[2]..............it was all over in 4th post.........and i started it again[9]
hmmmm....
manish sir! in ur post da equality sign shud not equal to sign ne coz RHS we λ2 and in LHS sirf λ
Eureka is also right ax only satisfies f(x+y)=f(x)f(y) but it doesn't satisfies....other condition f'(0)=11
I JUS LOVE THIS STATEMENT :
"ans sab method se ana chahiye... ye maths hai chem nahi"
BUT HEY AB IF f'(0) exists n is equal to 11 it means its derivative exists.........
unless u consider it is non differentiable at x=3; which wud b toooo hard on the paper setter thodi daya karo us becherre par... [1]
"ans sab method se ana chahiye... ye maths hai chem nahi"
yes true but what is the method here other than bhaiyyas
checking for functions isnt a method
subhash my connotation was to the statement in general.....
in this questn mayb ther doesnt existr a method.....
but the thot that in che n maths wenever 2 diff meth of solvign same sum exist then in math both lead to da same ans which is rarely the case in CHE....
SORRY CHEM LOVERS..... but i feel dats a fact
There is no mistake in my solution..
because if you see closely, it is given differentiable at 3 just because it says f'(3) = something
and f'(0)= something else.
Remove x from my solution.. replace it by 3..
then do all the steps that I did..
It will work.
sorry to everyone........i made a compelete blunder.............Yes Nishant Sir is correct...............GOIIT IS WRONG....
I have a little doubt
for f(x)=ax, is the condition f'(0)=11 true??
oh din read the 2nd part of ur message..
Even I am getting 33...
Where is the question from :(
its actually frm goiit test carnival.....(4 IIT JEE)
BUT ther r a NO. OF mistakes in it....
abt 10 in BITSSAT paper alone
it is none of these dear...........
it is Cauchy'2 2nd equation
=> f(x)=ax
f(3)=3 =>a3=3 =>a=31/3
we have to find f'(3)
so first get f'(x)=axloga
=>f'(3)=31/3 (3)log31/3
=>f'(3)=log3 [1]
ya right eureka. AND MAGIC MATH U REMEMBER THIS, THE FUUNCTION SATISFYING THE GIVEN GIVEN EUATION IS ax.
sry
But bhaiya just proved convincingly that it is 33.......so whose mistake is it...........bhaiya's and Magic Math's or goiit's?
i can only say that ans is log3....[2].......
i will try t ofigure out any calculation mistake here....[12]
f(x)=f(x).f(0)
so f(0)=1
f(x+h)-f(x)=f(x){f(h)-1}
f(x+h)-f(x)=f(x){f(h)-f(0)}
divide by h and take limit as h tending to zero..
f'(x)=f(x).f'(0)
so f'(3)=3.11=33
Function is...
y=λekx where λ,k are constant..
where λk=11 and 3=λe3k..
Arey yaar. Is proof to be given in accordance to the answer or the other way round?