If side of S1 is a, then side of S2 is a/√2, side of S3 is a/2 and so on...
Hence if area of S1 is A, then area of S2 is A/2 and so on.......
Area of Sn=A/(2)n-1
Can you carry on from here?
let S1,S2.... be squares such that for each n>or=1, the length of a side of Sn equals the length of a diagonal of Sn+1 . If the length of a side of S1 is 10cm , then for which of the following values of n is the area of sn less than 1 sq.cm
a)7 b)8 c)9 d)10
If side of S1 is a, then side of S2 is a/√2, side of S3 is a/2 and so on...
Hence if area of S1 is A, then area of S2 is A/2 and so on.......
Area of Sn=A/(2)n-1
Can you carry on from here?
If what i've given above is correct, then answer should turn out to be 8.
If my above method is wrong then I'm extremely sorry for wasting your time
it will not only be 8..
inequality is given...
u r absolutely correct..
Sn < 1
=> 100 < 2n-1 => 26 < 2n-1 (coz 27>100)
=> 6< n-1 => n>7
so ans is... b,c,d ........ i mean 8,9,10.