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Find xyz...

x+\frac{1}{y}=4 , y+\frac{1}{z}=1 , z+\frac{1}{x}=\frac{3}{7}

#Mathematics #Algebra

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7 Answers

1

dimensions (dimentime) ·2009-05-08 03:57:57

is it given that x,y,z are +ve reals ???

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11

Mani Pal Singh ·2009-05-08 04:00:12

nothing else is mentioned
if u have to take it
or it seems compulsory 4 u
then take it!!!!

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1

dimensions (dimentime) ·2009-05-08 04:11:26

arre, if x,y,z are to be +ve reals then no value of x,y,z, will satisfy it...!!!

if nothing is mentioned then they can be -ve

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11

Mani Pal Singh ·2009-05-08 04:14:55

yup u r right
then ur answer[7][7][7]

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9

Celestine preetham ·2009-05-08 08:53:44

3Â±√30 / 3+√30

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Celestine preetham ·2009-05-08 08:55:50

there are 2 ans as 2 sets of values possible

y= 1/4-X

z= 4-X / 3-X

xyz = X / 3-X

solve for X and sub

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Celestine preetham ·2009-05-09 03:53:04

confirm the correctness mani

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Your Answer

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