arre, if x,y,z are to be +ve reals then no value of x,y,z, will satisfy it...!!!
if nothing is mentioned then they can be -ve
Find xyz...
x+\frac{1}{y}=4 , y+\frac{1}{z}=1 , z+\frac{1}{x}=\frac{3}{7}
nothing else is mentioned
if u have to take it
or it seems compulsory 4 u
then take it!!!!
arre, if x,y,z are to be +ve reals then no value of x,y,z, will satisfy it...!!!
if nothing is mentioned then they can be -ve
there are 2 ans as 2 sets of values possible
y= 1/4-X
z= 4-X / 3-X
xyz = X / 3-X
solve for X and sub