I have a tiny doubt:
If a,b,c are roots of x2-3x+p=0 and
Can a quadratic equation have three roots?
If a,b,c are roots of x2-3x+p=0 and c,d are rooots of x2-12x+q=0 where a,b,c,d form a GP.
Prove that q+p/q-p=17/15
I have a tiny doubt:
If a,b,c are roots of x2-3x+p=0 and
Can a quadratic equation have three roots?
assuming a,b to be the roots of x2-3x+p=0
a+b=3 and ab=p
c+d=12 and cd=q
let r be the common ratio
b=ar, c=ar2 and d=ar3
a+b=3 implies a(1+r)=3
and c+d=12 implies ar2)1+r)12
so we get r2=4
(q+p)/(q-p)=(cd+ab)/(cd-ab)=(r4+1)/(r4-1)=17/15