GP

let 3 nos are removed from the set{2,22,23,24,.......2n}

the GM of remaining nos is 237/5.........find the value of n

partially a doubt :P

want to confirm the ans

8 Answers

1
mentor_Pritam ·

i think n=13 is the ans.
does it match with ur ans?

341
Hari Shankar ·

13 is right.

1
Che ·

yeah.....i was getting 13 only..

can someone complete this one.....

open to all...

1
Che ·

anyone trying this one ?

its a good q i must say.......

1
b_k_dubey ·

we have to deal with AM of exponents

suppose 2a, 2b, 2c are removed from the set

n(n+1)2 - (a+b+c) = 375(n-3)

since LHS is an integer RHS is also an integer, so n is of the form 5k+3 where k is a positive integer

now, 1+2+3 ≤ a+b+c ≤ n-2 + n-1 + n........using this and n = 5k+3

6 ≤ (5k+3)(5k+4)2 - 37k ≤ 5k+3-2 + 5k+3-1 + 5k+3

25k2 - 69k ≤ 0, 25k2 - 39k ≥ 0

from these two : k = 2, so n = 5k+3 = 13

this solution u can say is a by-product of one of Hari sir's solution :)

1
Che ·

yup.....tahts good [1]

1
Bicchuram Aveek ·

Is Prophet the pseudonym of Hari Sir ??

341
Hari Shankar ·

not pseudonym! username

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