collinear..... try finding the slopes
- Gaurav Gardi x1/y1Upvote·0· Reply ·2013-04-15 22:49:18
x1, x2, x3 are in GP and y1, y2,y3 are also in GP with same common ratio. then (x1,y1), (x2,y2)&(x3,y3) these are
a]vertices of a triangle
b]situated on a circle
c]collinear
d]situated on an ellipse
collinear..... try finding the slopes
x2/x1 = x3/x2 and y2/y1 = y3/y2
=> (x3 - x2)/(x2 - x1) = (y3 - y2)/(y2 - y1)
=> (y2 - y1)/(x2 - x1) = (y3 - y2)/(x3 - x2)