1its 7C5
If the domain of function is {-2,-1,0,1,2} and range is
{-4,-3,-2,-1,0,1,2,3,4}
how many increasing functions are possible that will satisfy f(n) not equal to +n or -n ?
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13 Answers
49if the thng is strictly increasing..(which requires the function to be one-one also!)
then answer is 9C5
71SInce the Domain is {-2,-1,0,1,2},
We have total 9C5 increasing functions possible at all.. But since f(n) ≠± n , hence the two option in the range are weeded out (for each value in Domain) . i.e., We have now 7 values in the Range for 5 values in Domain for the function to possible.
Hence, Total = 7C5
The Solution presented above has no guarantee of correctness and any damages due to it is totally subjected to the asker. :P
1yes,2 values are ignored,but only if domain is non zero?what if domain is 0?
THis is only a shortened part of the question.thanks vivek for attempting.
In Actual question,the domain was {-1005,-1004.........1004,1005}
and the range was {-2010,-2009,....2009,2010}.
can you answer this ?
71In that case we'll have total of 2n+1 terms in Range where n = 2010 and 2p (p=1005) terms in the domain.
So then it should be 2n-1 C 2p.
I have excluded zero..
Aisa kuch hai kya?
1yes,please vivek bhaiya,give some details,,how to count the no of increasing functions ?