2 Answers
Lokesh Verma
·2009-07-24 07:14:23
see some of the graph sof the day
or otherwise
first think of the points where sin √x is zero.. or where it is 1
then try to proceed..
sin2 is simpler....
Give it a shot :)
gaurav
·2009-07-24 07:37:01
but the prob. with dis is sin√x isn't continuous everywhere.................