1calling nishant sir,prophet sir and kaymant sir........!!!!
:-)
find the possible number of ordered triads (m,n,p)
where 1≤m≤100
1≤n≤50
1≤p≤25
and (2^m )+(2^n)+(2^p) is divisible by 3........
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6 Answers
13572m+2n+2p=(3-1)m+(3-1)n+(3-1)p=3x+(-1)m+(-1)n+(-1)p
So you have to to find when (-1)m+(-1)n+(-1)p is divisible be 3
This might help
13572n=(3-1)n=3n-nC13n-1+...+(-1)n=3x+(-1)n
2m+2n+2p=(3-1)m+(3-1)n+(3-1)p=3x+(-1)m+(-1)n+(-1)p
So you have to to find when (-1)m+(-1)n+(-1)p is divisible be 3
(-1)m+(-1)n+(-1)p is divisible by 3 only when
(-1)m+(-1)n+(-1)p=±3
1thank u sir.......i got the answer
the correct answer is
(50c1*25c1*13c1 )+ (50c1*25c1*12c1)
=31250