[1*9*100+2*9*101+3*9*102+4*9*103+...........+2000*9*102000]+2001
- Soumyabrata Mondal * last 1 is 10[power]1999Upvote·0· Reply ·2013-02-28 08:00:42
\hspace{-16}$How many digits are used in total to write the natural numbers \\\\ from $\bf{1}$ to $\bf{100 ^ {1000}.}$
[1*9*100+2*9*101+3*9*102+4*9*103+...........+2000*9*102000]+2001