11yes asish but how please explain
15 Answers
62what can u say aobut the expression that asish added to the original one?
11i get it that the second term is<1
but basically how did we get that term
62that is a tough one to answer... I mean it comes with practice subash...
It is like mroe the problems (or types) you have seen in the past.. more you can apply...
Now these kind of questions will be solvable by u too in the future... wont they :)
13This is an explanation for d first question asked by u...
(rt.3+1)^6 = I + f .......... integral + fractional part...
let F = (rt.3-1)^6 ....... F < 1
I+F+f=2(I').................... I' is an integer... observe...
since RHS is an integer, LHS should also be an integer ...... => F+f must be an integer
=> f+F=1.......... (since sum of two fractional parts cannot be ≥2)
hence to get an integer juzz greater than I+f, we must add 'F'...
hope its clear now... [1]
13similarly for second one... v can say d ans is (2+rt.3)^5 - (2-rt.3)^5... [1]
13sorry for d wrong ans... [2]
i'll try it tomorrow... dont post d answer atleast for others...