1l z2-3-4i l=5 take z2=x+iy and put it in da equ its becoming l x-3+i(y-4)l=5 or (x-3)2+(y-4)2=25 we get x=6 and y=8 lz2l=√62+82=10 lz1-z2l ≥ l lz1l - lz2l l or lz1-z2l ≥12-10=2.......min value is 2.
2 Answers
1
12nd circle is inside 1st circle
least distance between them = difference in their radii - distance between their centres
