A bit concerned about the equality case.
Rest is mere moonshine
If x , y , z are three real numbers not equal to 1 such that xyz=1
show that :
x2(x-1)2+y2(y-1)2+z2(z-1)2≥1
can this be done suppose x=12 and y=1/4,z=1/3;
thus re4placn9 the value in the eqtn ans is grtr than 1 hope dis cn b dne.......:p
\frac{x^2}{(x-1)^2}+ \frac{y^2}{(y-1)^2}+ \frac{z^2}{(z-1)^2}\geq 1
\iff \frac{{}\left (xy+yz+zx-3 \right )^2}{(x-1)^2(y-1)^2(z-1)^2}\geq 0
Which is true