3|x|2-5|x|+2>0
=> (3|x|-2)(|x|-1)>0
=>|x|<2/3 or |x|>1
=> -2/3<x<2/3 or x<-1 or x>1
so option (D)
|x|2 - |x| - 22|x| - |x|2 - 2 > 2 holds if and only if
(A) - 1 < x < -2/3 or 2/3 < x < 1
(B) -1 < x < 1
(C) 2/3 < x < 1
(D) x > 1 or x < -1 or -2/3 < x < 2/3
3|x|2-5|x|+2>0
=> (3|x|-2)(|x|-1)>0
=>|x|<2/3 or |x|>1
=> -2/3<x<2/3 or x<-1 or x>1
so option (D)