interesting proof.

prove that for all odd k
(1k + 2k + 3k + ... + nk) is divisible by n(n+1)/2.

you may use principal of mathematical induction.

7 Answers

11
Devil ·

You may also like this : http://www.math.rutgers.edu/~erowland/sumsofpowers.html

21
Shubhodip ·

Do u need a proof ? or its for others to try ?

71
Vivek @ Born this Way ·

It's for other to try!

3
h4hemang ·

thanks devil.
that link is interesting and helpful.

1
fahadnasir nasir ·

M ind

3
h4hemang ·

a hint.
S = (1^k + 2^k + 3^k + ... + n^k).
2S = (1^k + 2^k + 3^k + ... + n^k) + (n^k + (n-1)^k + ....... + 2^k + 1^k).
then use the fact (n^k) + (m^k) is divisible by (n+m) for odd k.

11
Sambit Senapati ·

that's nice

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