Algebra - IS THER A LOCUS FOR this un :

1

Pavithra Ramamoorthy ·2009-03-24 21:18:41

no yaar.......... y do u say dis now??????? do u ve d sol wit u????????

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21

tapanmast Vora ·2009-03-25 01:14:37

hmmmm YREAH!!!

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1

rajat sen ·2009-03-25 01:09:56

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1

ANKIT MAHATO ·2009-03-24 23:57:08

simple yaar

((1 + z)/z)⁶ = -1

now we can easily solve it ...

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24

eureka123 ·2009-03-24 23:50:48

does this help????

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106

Asish Mahapatra ·2009-03-24 22:08:43

bhaiyya im getiing .. z = (-1Â±i)/2

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1

Pavithra Ramamoorthy ·2009-03-24 22:02:43

YES BYAH... DIS S D WAY I DID .......

BUT I WEN WRON SOMEWHERE ELSE IN CALC.....

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1

Pavithra Ramamoorthy ·2009-03-24 22:00:58

PLS TELL ME HOW TO SOLVE IT...................;-)

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62

Lokesh Verma ·2009-03-24 22:00:11

does this help.. or am i blabbering!?
\left((Z+1)^3 \right)^2=(iZ^3)^2

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21

tapanmast Vora ·2009-03-24 21:59:21

NO......
I say this coz :

the LOCUS u r suggesting is wrong :( jus take ne point on ur locus and c wether it satisfies :

(z+1)^6 + z^6 = 0

U shal hav ur answer

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11

Mani Pal Singh ·2009-03-24 21:03:03

tapan wat r u trying to ask
please make it more clearer[1]

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21

tapanmast Vora ·2009-03-24 21:17:24

Ram : | -1 | = 1 hota hai......... i hope u din make this mist

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1

Pavithra Ramamoorthy ·2009-03-24 21:14:37

2x²+2y²+2x+1=0

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11

Mani Pal Singh ·2009-03-24 21:13:59

bhai roots chayiye ya fir locus
question will become different
if u need rootd then i think i have a method

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21

tapanmast Vora ·2009-03-24 21:13:43

ya I did that!!!

Wats ur locus?? can u give ur eqtn in a proper form pl...

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1

Pavithra Ramamoorthy ·2009-03-24 21:12:40

ve d solution??????????????

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1

Pavithra Ramamoorthy ·2009-03-24 21:11:55

try solvin it by takin modulus on bth sides.....

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21

tapanmast Vora ·2009-03-24 21:11:08

kaise yaar the power is "6" not 2

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Pavithra Ramamoorthy ·2009-03-24 21:10:02

taking z= x+iy

locus s 2x²+2y²+2x+1=0????????????

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21

tapanmast Vora ·2009-03-24 21:05:55

arre yaar!!!

FIND LOCUS OF Z in tis

(z+1)^6 + z^6 = 0

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IS THER A LOCUS FOR this un :

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