1Rahul,there is no option like that.
Number of zeroes in the end in the product of 56 × 67 × 78 × ........× 3031 is
(A)111
(B)147
(C)137
(D)136
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13 Answers
1rahul subho ki baat yaad hai [3].aisa mat kar warna maths tujhse badla legi![3][3].option toh padha kar!
1@!^--_--^!
bhaiya i think subhodip told the concept and there is nothing more than that to the problem...just "mere clerical" work...!
36One of the logic which can work here is,
odd x odd can never end with the digit 0
even x odd or, even x even can end with the digit 0
it can be done very very and very easily....!!
shall i post the solution?
36Do this,
Only multiply those terms which is a multiple of 5 or 2 eg. 26, 25 and all....
At last u'll get, 5137 x 2>137 but 2>137 is of no use, as 2n can never end with a digit zero for any iteger n
so, the answer is 137 i.e., option c is correct :D
i.e., Subhodip bhai's logic is correct