Log

log(a-bx)=0
loga/logbx=0
soln: a=1,
b,x=(0,∞)-{1}

The equation is not clear

if log (a-bx) = 0 , then the only soln is -> a-bx=1

sorry ive committed a foolish mistake:
loga-logb=log(a/b)
and
log(a-b)≠loga/logb

In that case, if a solution for x is required, all we get is x=(a-1)/b. Khatam. Btw, a solution was asked for. But what we have been provided with is an expression, log(a-bx)=????? if it is 0 on the RHS,
the solution x=(a-1)/b holds.