(z3 +3z -1) +i(2z+a) =0
for real root , 2z+a =0 and z3 +3z -1=0
from the above eqns , your answer seems correct.
Q: If z3+(3+2i)z+(ai-1) = 0 has a real root, then ' a ' lies in the interval (a ε R) :
My Ans: (-1,0) , Given answer (-2,3)
(z3 +3z -1) +i(2z+a) =0
for real root , 2z+a =0 and z3 +3z -1=0
from the above eqns , your answer seems correct.