$Find Max. and Min. value of $\sqrt{x^3-6x^2+21x+18}$\\\\ Where $x,y\in R$ and $-\frac{1}{2}\leq x\leq 1$
1Let us assume a function G(x)=x3-6x2+21x+18
G1(x)=3x2-12x+21=3(x2-4x+7)
G1(x)>0 for all x as D<0 and a=3>0
therefore G(x) is a strictly increasing function
Now G(-1/2)=47/8
G(1)=34
as G(x) is strictly increasing the given function will also be strictly increasing in its domain
so minimum value=√47/8
Max Value=√34
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U don't talk about the fight club
Second Rule Of Fight Club
U DON'T TALK ABOUT THE FIGHT CLUB
1wat Right my answer or the shit I wrote??
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