it represents any any random complex number with |z|=r , x=|z-3|,y=|z-6i|
now applying cosine law for the two triangles , wee get
x2=r2+9-6rcosθ and
y2=r2+36-12rsinθ
adding both of them and adding r2 both sides
|z|2+|z-3|2+|z-6i|2=3(r2+15-2r(cosθ+2sinθ))
this is quadratic in r and te minimum value of any quadratic with a>0 is -D4a
hence
f(min)=15-(cosθ+2sinθ)2
this expressions min value is when (cosθ+2sinθ)2 attains max =5
hence min value is ( 15-5 ) *3 =30
find the min possible value of \left|z \right|^2+\left|z -3\right|^2+\left|z -6i\right|^2
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6 Answers
xYz
·2010-03-04 20:25:19
Che
·2010-03-04 20:51:55
the given represents the sum of the sqaures of the distances of a point z from vertices of the traingle having cordinates (0,0) (3,0) (0,6) and that z point is centriod of the triangle
Hari Shankar
·2010-03-04 22:28:14
In fact If you write z=x+iy you will notice that that the expression can be written as F(x) + G(y). We can separately minimise F and G and thus obtain the minimum value of the given expression.
That is how we see that the minimum is obtained when z is the centroid. (In fact i have seen this result in one of the X Class math guides!)