1p(A) matlab
probability that A speaks truth is 4/5. A coin is tossed. A reports that a head appears. wat will be the probability if actually there was a head??????????????????????????????????????????????????????
i want solution
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19 Answers
1don't confuse me.............. ye bta tu kaunse college mein hai
1thankssssssssssssssss priyam.........
vishal main ye hi puch ra hu ki +2 kaunse college mein padhate hain
1arey we dont hav to study ncert in college naa so i gave away my ncert so i dont hav to see that example of ncert [4][4]
33P(getting head).P(Telling it head|Head occur)
P(gettin head).p(Telling it head|Head occured)+P(Getting tail).P(Telling it head|Tail occured)
Is it now clear.. [1]
131/2*4/5+1/2*1/5
P(Head appears)*P(A speaks truth)+P(tail appears)*P(A lies)
sorry
i din read the q[3]
doing stupid things
1apply baye's theorem
p=(1/2*4/5)/(1/2*4/5+1/2*1/5)
=(4/5)/1
=4/5
[4][4]
pehli baar kisi probabolity Q ka jawab diya hai hope i m rite
33CBSE me post :4 jasie solve karo...
Usko kuch kahte hai naa... 'Baey's theorem' ya kuch
1no bro.............. answer is 4/5, lekin cbse mein kaise solve karenge
33Another straight logic...
If he speaks truth 4/5 then prob of actually 6(when he reported 6) is probability that he speaks truth... =4/5