I present myself a honorary " Fields Medal " for the most beautiful observation my " brain " has ever made : )
For any " x " ,
x @ 3 = x + 3 + 3 x + 9x + 3 = 4
Hence , the required result = ( ( 4 @ 2 ) @ 1 ) = 10629
now no questions involving numbers like 2011 ,2010...
Let a@b be defined as a@b=(a+b+ab+9)/(a+b);
then ((((((......((5000@4999)@4998)@4997@......(3@2)@1) EQUALS??????
I present myself a honorary " Fields Medal " for the most beautiful observation my " brain " has ever made : )
For any " x " ,
x @ 3 = x + 3 + 3 x + 9x + 3 = 4
Hence , the required result = ( ( 4 @ 2 ) @ 1 ) = 10629
@Ricky - thats clever, did the question expect us to do by the same method?