to add to the beauty of soln...
in third line ..............in brackets (as x≠1)
xlog10x2 = 10 x2
we can write this as...
logx(10x2) = log10 x2
=> logx10 + 2 = 2 log10 x
take log10 x = y
then the equation becomes:
1/y + 2 = 2y
=> y= (1±√3)/2
x = 10y
we will get two values of y ... so two values of x..
to add to the beauty of soln...
in third line ..............in brackets (as x≠1)
Me:are second step kya ki ho
Sky: ??
taken log
me: no one can solve it
Sky: like x^y= p
so log p base x =y
like dis
me:
how u did it ... no one can solve it :P