Number of soltions

1)Find the number of solutions of the equation
here [.] is greatest integer function

2) evaluate - \int_{0}^{1}{(1+e^{-x^2}})dx

3) \textup{if }I_n=\int_{0}^{1}e^x(x-1)^n \textup{dx} \textup{ and } I_p=24e-65 \\\textup{find p}

Help in these plz.

12 Answers

1
kamalendu ghosh ·

is p=4 in the 3rd q??

1
kamalendu ghosh ·

for q no. 3 express In in a reduction form and solve... it will be something like
In=(-1)n-nIn-1.... check for urself...

1
Rasheed Ahmed ·

din get that reduction.....[2]

plz someone solve these.

1
kamalendu ghosh ·

use by parts where u integrate the ex and differentiate (x-1)n

1
utd4ever ·

yeah thats right ans is 4 you will get
In+nIn-1=(-1)n+1

1708
man111 singh ·

is the ans of 1 st question is = 0

106
Asish Mahapatra ·

1. LHS= even, RHS = odd

1
raja ·

@asish - so u mean there are no solutions to x^2=x ?

23
qwerty ·

asish is correct abt d 1st one, i.e no solutions

1
vinutha student ·

for the 2nd... ∫(1+e-x2) dx = ∫(1+1-x21!+x42!-x63!+.......∞)dx

integrating and applying the limits from x=0 to x=1,

=(2-13.1!+15.2!_17.3!+........∞)

is dis the ans???

1
nikunj ·

1
Let I=∫1+e-x2
0
e-x2 is decreasing function for 0<x<1

e0<e-x2<e-1
1<e-x2<1e
2<1+e-x2<1+1e
∫2 <∫1+e-x2 <∫1+1e

2(1-0) <∫1+e-x2 < 1+1e(1-0)

2<I<1+1e

106
Asish Mahapatra ·

@raja: i meant that Q1. LHS is an even integer while RHS is an odd integer.

so we have no solutions

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