If m and n are any 2 odd positive integers with n<m then largest positive integer which divides all numbers of the form (m2-n2).(my ans is cumin 4 but it is given 8).
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1 Answers
Lokesh Verma
·2009-10-21 09:07:20
Answer is 8 because
m = 2x+1
n= 2y+1
m2-n2 = (m-n)(m+n) = (2x-2y)(2x+2y+2) = 4(x-y)(x+y+1)
if x and y are both odd or even then x-y is even
else (x+y+1) is even.......
Hence the total number is a multiple of 8