f(x) = ln(x2 + 3x +1)
let, y = ln(x2 + 3x +1).
or, ey = (x2 + 3x +1).
or, x2 + 3x +1 - ey =0
0r, x= -3 ± √9 - 4 + 4ey2.
or, x= -3 ± √5 + 4ey2.
as x belongs to [1,3]
x can not be -3 - √5 + 4ey2.
thus, the inverse is,
f-1(x) = -3 + √5 + 4ex2.
f(x) = ln(x2 + 3x +1)
let, y = ln(x2 + 3x +1).
or, ey = (x2 + 3x +1).
or, x2 + 3x +1 - ey =0
0r, x= -3 ± √9 - 4 + 4ey2.
or, x= -3 ± √5 + 4ey2.
as x belongs to [1,3]
x can not be -3 - √5 + 4ey2.
thus, the inverse is,
f-1(x) = -3 + √5 + 4ex2.