one liner

find min. value of
[(x+1/x)6-(x6+1/x6)-2]/[(x+1/x)3+(x3+1/x3)]
for x>0

and [.] doesnt mean GINT

7 Answers

1
°ღ•๓яυΠ·

6
u said one liner so .....lafda kara

did virtually

tellmeh if wrng i'll try:P

edited d post meine x>0 dekha ni tha

24
eureka123 ·

ans is 6.....u r near

11
Mani Pal Singh ·

we know the

x+1/x≥1 (AM>GM)
--------
2

x + 1/x ≥2

similarly we get the min value of x6+1/x6≥2

so min value is

[26-2-2]/[8+2]
so the answer is

6

1
Optimus Prime ·

the correct answer is 6

24
eureka123 ·

better approach:

put (x+1/x)3=a
and x3+1/x3=b

the expression becomes
a2-b2/a+b
=> a+b
=> 3(x+1/x)

we know that x+1/x≥2
=> expression has min value equal to 6

which is possible when x=1(becoz then only AM=GM)

1
°ღ•๓яυΠ·

yeah thats 6 ...............sorry ..........i took x=-1............dekha ni ki x>0

so best approach .put x=1

24
eureka123 ·

yeah thats good for objective papers...[1][1]

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