29arey yaar it's summation 1+1+1+1+1...(n+1) times so it is equal to n+1 coz s=0 from 0 to n ..if s =1 to n then the summation wud be n..
\sum_{s=0}^{n}{(1)} = ( n + 1 )
how is it coming....
or shud we just remember it
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29
11due to a problem of my mouse or my browser two threads are being posted for a single topic.....
so i am posting another doubt from binomial....so that the thread does not go into waste...[2][2]
The Value of
\sum_{r=0}^{n} \sum_{s=1}^{n} nCs sCr is
r ≤ s
a)3n - 1 b)3n + 1 c)3n d)N.O.T
answer is a