P&C-3

8x9x5 + 5 ???

365

1st leave the case of 5..
Then the hundred's place can be filled in 8 ways viz 1,2,3,4,6,7,8,9
again the ten's place can be filled in 9 ways since 5 is excluded bcoz the the next digit wud be 7 and it will nt be an even number
and lastly the units place can be filled in 5 ways(0,2,4,6,8)

so total number of digits=8*9*5=360

Now the case of 5..
If the first digit is 5 the 2nd is 7...therefore the ten's place can now be filled in 5 ways..

so total digits formed=360+5=365

4???Am I missing out on something?