P&C Challenge 5

BITSAT Guidance › Algebra questions › P&C Challenge 5

There are 10 points in a plane of which no three are collinear and 4 points are concyclic.Find the number of different circles that can be drawn through atleast 3 of these points..

Kindly explain also..

#Mathematics #Algebra

UP 0 DOWN 0 0 2
Post on FacebookPost anonymously?

2 Answers

Anirudh Kumar ·2009-10-21 06:12:20

for getting a circle we need 3 points .

for selecting three points from 10

¹⁰C₃

but selection from those four concyclic points will lead the same circle .

total no of circles

¹⁰C₃ - ⁴C ₃ +1

UP 0 DOWN 0
Post on FacebookPost anonymously?

Rocky Crazy ·2009-10-21 06:23:20

Thanks Anirudh..

UP 0 DOWN 0
Post on FacebookPost anonymously?

Your Answer

Basic Integral Calculus Operators Symbols Matrix Cases

√ √ || {} [] () → ~ ^ x x x → → ln log lg lim lim cos sin tan cot arcsin arccos arctan

∫ ∫ ∫ ∫ ∫ ∬ ∬ ∬ ∬ ∬ ∭ ∭ ∭ ∭ ∭ ⨌ ⨌ ⨌ ⨌ ⨌

∑ ∑ ∑ ∑ ∑ ∮ ∮ ∮ ∮ ∮ ∏ ∏ ∏ ∏ ∏ ∐ ∐ ∐ ∐ ∐

+ - × ÷ ± ∓ = ∪ ∩ ≠ ∼ ≈ ∅ ∀ ∃ ∈ ∋ ∝ ≤ ≥ ≃ ≅ ≡ < > ≪ ≫ ⊂ ∉ ⊃ ⊆ ⊇ ⇒ ⇐ ⇔ ⇒ ⇐ ⇔ ⇑ ⇓ ⇕ → ← ↔ → ← ↔ ↑ ↓ ↕ ↖ ↗ ↘ ↙ ↪ ↩ ⇀ ↼ ⇁ ↽

° ∂ ∞ α β γ δ θ λ μ ν ξ π ρ σ φ ω ε ƒ κ τ υ Γ Δ Λ Σ Π Ω

Close [X]

P&C Challenge 5

2 Answers

Your Answer

Add Image

Similar Questions