P&C Special from the Dark Knight

JEE Mains 2015 Tutorials › Algebra questions › P&C Special from the Dark Knight

If the no. of ways of selecting n cards out of unlimited no. of cards bearing the nos. 0,9,3 so that they cannot be used to write the no. 903 is 93, then n is :

A. 3
B. 4
C. 5
D. 6

#Mathematics #Algebra

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5 Answers

Bicchuram Aveek ·2009-11-14 23:14:56

neone watching it ?????

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Lokesh Verma ·2009-11-16 03:05:29

I din get the question at all.. din make much sense to me!

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Bicchuram Aveek ·2009-12-15 23:28:58

Sir even I can't understand it ... else why should I post a doubt ?

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Subhomoy Bakshi ·2009-12-15 23:33:38

most probably the sum means that we can choose n cards such that either of 9 or 0 or 3 is not chosen in each of cases

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Soumi Dasgupta ·2009-12-16 21:10:42

But it's given dat the cards bear the nos. 0,9,3 only !!! What do they mean by "unlimited" no. of cards???

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Basic Integral Calculus Operators Symbols Matrix Cases

√ √ || {} [] () → ~ ^ x x x → → ln log lg lim lim cos sin tan cot arcsin arccos arctan

∫ ∫ ∫ ∫ ∫ ∬ ∬ ∬ ∬ ∬ ∭ ∭ ∭ ∭ ∭ ⨌ ⨌ ⨌ ⨌ ⨌

∑ ∑ ∑ ∑ ∑ ∮ ∮ ∮ ∮ ∮ ∏ ∏ ∏ ∏ ∏ ∐ ∐ ∐ ∐ ∐

+ - × ÷ ± ∓ = ∪ ∩ ≠ ∼ ≈ ∅ ∀ ∃ ∈ ∋ ∝ ≤ ≥ ≃ ≅ ≡ < > ≪ ≫ ⊂ ∉ ⊃ ⊆ ⊇ ⇒ ⇐ ⇔ ⇒ ⇐ ⇔ ⇑ ⇓ ⇕ → ← ↔ → ← ↔ ↑ ↓ ↕ ↖ ↗ ↘ ↙ ↪ ↩ ⇀ ↼ ⇁ ↽

° ∂ ∞ α β γ δ θ λ μ ν ξ π ρ σ φ ω ε ƒ κ τ υ Γ Δ Λ Σ Π Ω

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P&C Special from the Dark Knight

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