sum of the digits to be even are in the.following cases
1). 4 odd and 1 even------5C4*5C1
2). 2 odd and 3 even---5C2*5C3
3) 5 even------5C5
therefore total no. of combinations---36(sum of the above cases)
the 5 digits will also permute in 36* 120 ways viz. 1080
but in 24 cases ,zero. will be the first digit
therefore no. of ways---1080-24=1056
The number of 5 digit numbers such that the sum of their digits is even is?
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2 Answers
Ketan Chandak
·2013-03-30 00:21:57
There are 90,000 five digit numbers..in half of them sum of the digits will be even and likewise sum will be odd for the other half...so 45,000.
- Swarna Kamal Dhyawala thank u
Upvote·0· Reply ·2013-03-30 10:30:20
Dwijaraj Paul Chowdhury
·2013-03-29 17:45:43