p n c

8 Answers

1
Anirudh Kumar ·

is the ans to the first ques

101C2 - 352C2 = 1275

71
Vivek @ Born this Way ·

352C2 .. What for is this part? can you explain your solution please.

71
Vivek @ Born this Way ·

"ways to choose 3 balls of all
minus ways not to choose any black ball "

i.e., 9C3-6C3 = 64 (Balls of same color are different)

I don't take credits

49
Subhomoy Bakshi ·

is it in any chance 103C2

then whom do u give credits??

30
Ashish Kothari ·

For the 1st question,

Let the shares to each son be S1, S2, S3.

S1 + S2 + S3 = 101

No. of integral solutions=100C2

Now, to remove those cases where one son gets more shares than the combined total of other two,

S1 + S2 ≤ 50

or,

S1 + S2 + x = 50

x ≥ 0

S1 = 1+ a [a≥0]

S2 = 1+ b [b≥0]

therefore,

a + b + x = 48

No . of integral solutions = 50C2

There will be three such cases.

So, no of ways to divide the shares = 100C2 - 3( 50C2)

71
Vivek @ Born this Way ·

Thanks!!

71
Vivek @ Born this Way ·

choosing two numbers from 1,2,3 where repetitions are allowed

Ye wali chiz ek baar aur batao na!!

1
EmInEm ·

http://www.targetiit.com/iit-jee-forum/posts/area-volume-18431.html

Your Answer

Close [X]