p[robablity]

Ans a

baye's theorem should do it

1/6

Using bayes thm,

P=(1/2*1/10)/1/2*1/10+1/2*1/2

=1/6

oops..!!!...late!

i got 1/3 by baye's

can u pl show sum workin

prob of getting 6:-
first die=0.1
second die=0.5
total prob of getting 6=0.6

prob of first die getting six= 0.1/0.6 = 1/6
so ans a

@tapan...u might hav made sum calculation error..!