333expression is always negative for negative x.f(0)=-2.f(1)=2.=>box p=0.
again,f(2) is negative.box q=1.f(3)is positive.box r=2.
therefore in AP,i suppose.
If f(x)=3x3-13x2+14x-2 and p,q,r are roots of f(x)=0 such that p<q<r,then
1),[q],[r] where [.] denotes greatest integer function,are in
A)A.P
B)G.P
C)H.P
D)A.G.P
2)\fn_jvn \lim_{n\rightarrow \infty }(p)^{n!}(q)^{1/n} =
A)0
B)1
C)e
D)e2
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4 Answers
333
1057sorry...the first question is (box)(p),[q],[r].Actually the p doesn't work in boxes as it denotes power.. :P
333no need to find the roots...differentiate once...check roots of f'(x).between two roots,we have one root of f(x).see where sign is changing and you just need the box of it..so its easy.