1for n=1, period is 2a....
for n=2, period is 3a
for n=3, period is 4a
so for n=n, period is (n+1)a
\sum_{k=0}^{n}{f(x + ka)} = 0
is this functn periodic ??
if yes, fid its period
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9 Answers
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1ok for n=1...
f(x)+f(x+a)=0
substitute x as x-a
f(x-a)+f(x)=0
subtract both....
f(x-a)=f(x+a)
substitute x as x+a
f(x)=f(x+2a)
so period is 2a for n=1.....
in d same way we can do the same for others....
and by generalising the result we get d period as (n+1)a
1oi prateek yaar.................wat i meant was ill type and post d solution