6 apples and 6 mangoes are to be distributed among 10 boys so that each boy gets atleast 1 fruit.Find the number of ways in which the fruits can be distributed.
1057is the answer 180?
Soumyabrata Mondal kaise kiya???
Akshay Ginodia answer is 26250 and whoever does it plz give the soln. ...i don't know how to solve it
1057first make sure each boy gets a fruit.3 cases:
1)6 Mangoes,4 Apples.The rest 2 apples can be given in 10C2 ways.
2)4 Mangoes,6 Apples.The rest 2 mangoes can be given in 10C2 ways.
3)5 Mangoes,5 Apples.The rest 2 fruits(1 apple and 1 mango)can be given in 2x10C2 ways.
Total ways=4x10C2 ways=180.
1057are all the 6 mangoes different? :P
Akshay Ginodia heheh..no :P
Hardik Sheth mangoes r the same but boys are different.hence you r missing out on a lot of combinations by just assigning (6+4)(4+6)(5+5)..
333there are two cases-
CASE 1:
one boy takes three apples others get one each.
CASE 2:
two boys take two each and rest take one.
Case 1
we have to select the guy taking 3,which can be done in 10C2 ways.
part 1-all apples---remaining fruits (3 apples + 6 mangoes) among nine in 9C6 ways.
part 2-all mangoes---remaining fruits (6 apples + 3 mangoes) among nine in 9C6 ways.
part 3-2 apples 1 mango---remaining fruits (4 apples + 5 mangoes) among nine in 9C5 ways.
part 4-1 apples 2 mango---remaining fruits (5 apples + 4 mangoes) among nine in 9C5 ways.
for case 1-10(84+84+136+136)=4400.
now someone do case 2!!
Hardik Sheth 10 c 1 ways..not 10 c 2Akshay Ginodia ya thats what i had done but somehow the answer is not coming out to be rightHardik Sheth there will be 9 cases for the 2 boys one...3*3 as aa,am,mm are possibilities for the boys wher a is for apple and...