1take n=1;
u might b able to get the answers.......
sometimes this trricckk also work...
although i hate tricks...
but nowadays i feel its useful...:(
A QUE FRM GOIIT........ NO ONE THER CARED TO ANSWER IT..... NICE ONE THOUGH.....
A regular polygon with vertices C1, C2, C3,.............Cn-1, Cn are inscribed in a circle with the centre C0
Q.1. If n is a multiple of 6, then total number of isosceles (including equilateral) triangles can be formed by joining three of the vertices of the polygon are
(a) n2 - 2n
(b) n2 - 8n/3
(c) n2 - 5n/3
(d) none of these
Q.2. If n is an odd number and a multiple of 3, then total number of isosceles (including equilateral) triangles can be formed by joining three of the vertices of the polygon are
(a) n2 - 2n
(b) n2 - 8n/3
(c) n2 - 5n/3
(d) none of these
Q.3. If n is even number and not a multiple of 3 then total number of isosceles (including equilateral) triangles can be formed by joining three of the vertices of the polygon are
(a) n2 - 2n
(b) n2 - 8n/3
(c) n2 - 5n/3
(d) none of these
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15 Answers
1
21genius how will dat n=1 trick work here??
but did you notice that if n=3, that is jus 1 equi triangle,
ans says C???
hows dat possible?????
13for Q.3.Putting n=4 and n=8 i m getting none of these[2]
for Q.1.Putting n=6 i m getting none of these[2]again
1Q1 most probably answer is d as i made the figure and got more than 28
13yup.....so the ans
Q.1.Putting n=6 none of these
Q.2 Putting n=3 b
Q.3.Putting n=4 and n=8 none of these
PS: Tricks are useful