permutations and combinations

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A BADMINTON CLUB HAS 10 COUPLES AS MEMBERS .THEY MEET TO ORGANISE A MIXED DOUBLE MATCH .IF EACH WIFE REFUSES TO PARTNER AS WELL AS OPPOSE HER HUSBAND IN THE MATCH THEN IN HOW MANY WAYS CAN THE MATCH BE ARRANGED??

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Mani Pal Singh ·2009-03-17 00:31:55

¹⁰C₂ x ⁸C₂ X2

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Lokesh Verma ·2009-03-17 00:35:03

good work manipal

Surbhi did you understand the proof?

first chose the 2 men

10C2 ways

then their wives cannot play

hence we have to chose 2 women from 8

hence 8C2

now we can have 2 teams for each such combination of 4 people.. (Mixed Doubles)

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Surbhi Shah ·2009-03-17 00:42:41

thanks i got it

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Surbhi Shah ·2009-03-17 00:43:53

can you have a look at all my other questions ? please !!

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Basic Integral Calculus Operators Symbols Matrix Cases

√ √ || {} [] () → ~ ^ x x x → → ln log lg lim lim cos sin tan cot arcsin arccos arctan

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° ∂ ∞ α β γ δ θ λ μ ν ξ π ρ σ φ ω ε ƒ κ τ υ Γ Δ Λ Σ Π Ω

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permutations and combinations

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