total permutations - 2*6!*3! - [(6!*3!)/2]
29. The number of permutations of the word
HINDUSTAN such that none of the three
patterns HIN, DUS, TAN occurs is
(1) 169194 (2) 166680
(3) 169190 (4) 166670
-
UP 0 DOWN 0 0 4
4 Answers
ДвҥїÑuÏ now in medical c
·2009-05-19 23:35:09
9!/2!-[7!+(7!/2!-5!)+7!-5!-5!+3!]=169194
long before i did it on tiit.....