11either i am not getting ur question
or
u r asking an obvious question
how will u add all the numbers doesn't matter how they r placed
12 Answers
11
1
"how will u add all the numbers doesn't matter how they r placed"
sorry i din get u [2]
11if u add 2+3+4+5+6 or 3+2+4+5+6 or 6+5+4+3+2
u will get the same result[3]
1ys ......c nw if u consider frm d first row ....say 1 nw u cnt conisder d no 2 b frm d firt colum ,.....if u consider d no 2 b frm d 3rd row ....say 19 so nw u cnt considr any no frm d third colum...gettin........??
just an xample.consider . nos frm d diagonal........ :)
1@ manipal
but d thing says 8 numbers such that
it is exactly one from each row and one from each column
so u can't choose 2 to 6 becoz they're in same row
u shud choose sumthing like
1 + 10 + 27 + 20 + 45 + 38 + 55 + 64 = 260
no nos. from same row & col.
11k
now i got ur question [1]
now i will give logical reason if i find 1
1hey c thses nos form Ap.....so..............nw wen u selct .one n rejct one....n do like this.............they add up to 260
1it is evident by lukin it...but i donno how to prove it mathematically...[7]
341Any number in the grid is obtained by the formula 8(i-1)+j
Since we are summing over all rows and columns i runs from 1 to 8 and j too from 1 to 8.
Hence irrespective of how the numbers are chosen, the sum of numbers obtained will be \sum_{i,j =1}^8 8(i-1) + j = 8 \sum_{i=1}^8 + \sum_{j=1}^8 j - 8 \sum_{i=1}^8 1 = 260