11ok
II)
AM = a + b/2
Gm = √ab
a + b)/2 -√ab> 0
a + b - 2 √ab>0
(√a - √b)2> 0
Therefore the Am is more than GM
If a,b are 2 different positive no. then prove that
I) A.m ,G.m ,H.m are in G.p
(II) A.m > G.m> H.m
Plz... Guide me guys
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8 Answers
11
62AM is given by (a+b)/2
GM is √(ab)
HM is 2ab/(a+b)
what do you have to prove that they are in GP?
AM.HM=GM^2
Is that obvious now?
1I think
(I)
G.M/A.M = 2√ab/a+b →1
H.M/G.M = 2√ab/a+b →2
Then they are in G.P
62yes sabitha..
why are you not sure on this one !!
Be confident :)