polynomial equation

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prove that nth degree polynomial equation has n roots.

#Mathematics #Algebra

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Vivek @ Born this Way ·2010-09-06 01:05:28

This may help

http://en.wikipedia.org/wiki/Nth_root

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Dr.House ·2010-09-06 12:53:01

a much more rigorous work can be found here:

http://www-history.mcs.st-and.ac.uk/HistTopics/Fund_theorem_of_algebra.html

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kvenkatasanjeev ·2010-09-07 06:26:23

applying simple logic that polynomial of degree two has two roots similarly polynomial of n degree has n no; of roots use brain it will simple crack iit

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Vivek @ Born this Way ·2010-09-08 01:43:02

She needed proof. So we gave her links for that. By the way, they might also be given in some elementary text books.

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Hari Shankar ·2010-09-09 01:12:16

If you find it in a text book, let me assure you, that textbook isnt elementary!

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Basic Integral Calculus Operators Symbols Matrix Cases

√ √ || {} [] () → ~ ^ x x x → → ln log lg lim lim cos sin tan cot arcsin arccos arctan

∫ ∫ ∫ ∫ ∫ ∬ ∬ ∬ ∬ ∬ ∭ ∭ ∭ ∭ ∭ ⨌ ⨌ ⨌ ⨌ ⨌

∑ ∑ ∑ ∑ ∑ ∮ ∮ ∮ ∮ ∮ ∏ ∏ ∏ ∏ ∏ ∐ ∐ ∐ ∐ ∐

+ - × ÷ ± ∓ = ∪ ∩ ≠ ∼ ≈ ∅ ∀ ∃ ∈ ∋ ∝ ≤ ≥ ≃ ≅ ≡ < > ≪ ≫ ⊂ ∉ ⊃ ⊆ ⊇ ⇒ ⇐ ⇔ ⇒ ⇐ ⇔ ⇑ ⇓ ⇕ → ← ↔ → ← ↔ ↑ ↓ ↕ ↖ ↗ ↘ ↙ ↪ ↩ ⇀ ↼ ⇁ ↽

° ∂ ∞ α β γ δ θ λ μ ν ξ π ρ σ φ ω ε ƒ κ τ υ Γ Δ Λ Σ Π Ω

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polynomial equation

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