We have,
[ 3√k ] = 1 , when k varies from 1 to 7
[ 3√k ] = 2 , when k varies from 8 to 26
[ 3√k ] = 3 , when k varies from 27 to 63
and so on.
From here, we can solve the problem.
We have,
[ 3√k ] = 1 , when k varies from 1 to 7
[ 3√k ] = 2 , when k varies from 8 to 26
[ 3√k ] = 3 , when k varies from 27 to 63
and so on.
From here, we can solve the problem.
I'm posting a similar problem which came to my mind. I don't know whether it has been already discussed or not. Let me know if it has been.
We need to find A. [.] is Floor Function.
It easy to guess, But a good solution is expected